Question 34286
log10 using base of 100 = (1/2)
That means 100^(1/2)=10
Your problem becomes 
x=8(1/2)=4

=logaK-(logM + logbA)
=loaK-(logb(MA))

=logb(2y+3) - logb(y+3)^(1/2)
=logb[(2y+3)/sqrt(y+3)]
Cheers,
Stan H.