Question 283141
If the numerator reads 5-(2/(n-3))

{{{5-(2/(n-3))}}} 
and the denominator reads
{{{4-(1/(n-3))}}} 

and the whole mess is
{{{(5-(2/(n-3)))/(4-(1/(n-3)))}}} 


then multiply the whole shebang by {{{(n-3)/(n-3)}}}
which will get you 
{{{(5(n-3)-2)/(4(n-3)-1)}}}
{{{(5n-15-2)/(4n-12-1)}}}
{{{(5n-17)/(4n-13)}}}