Question 283099
The answer entails finding the length of the diagonal of the square "ring" which is easily accomlished using the Pythagorean theorem {{{c^2 = a^2+b^2}}}.
Here, a & b (the lengths of the sides of the square) = 20 feet each and c will be the length of the diagonal and thus the distance separating the two boxers when they are in their respective corners.
{{{c^2 = a^2+b^2}}} Substitute a = 20 and b = 20.
{{{c^2 = 20^2+20^2}}}
{{{c^2 = 400+400}}}
{{{c^2 = 800}}} Take the square root of both sides.
{{{c = sqrt(800)}}}
{{{c = 28.28}}}feet.
The boxers are 28.28 feet apart.