Question 283100
You could try this:
{{{5x+x(x-2) = 0}}} Factor an x.
{{{x(5+(x-2)) = 0}}} Simplify.
{{{x(3+x) = 0}}} Apply the zero product rule: If a*b = 0, then either a = 0, or b = 0, or both, so...
{{{highlight(x = 0)}}} or {{{3+x = 0}}} and so {{{highlight(x = -3)}}}
The solutions are: {{{x = 0}}} and {{{x = -3}}}
The x-intercepts are: (0, 0) and (-3, 0)