Question 282917
{{{5x+x(x-2)=0}}} Start with the given equation.



{{{5x+x^2-2x=0}}} Distribute.



{{{x^2+3x=0}}} Combine like terms.



{{{x(x+3)=0}}} Factor out the GCF 'x'.




Now set each factor equal to zero:


{{{x=0}}} or  {{{x+3=0}}} 



{{{x=0}}} or  {{{x=-3}}}    Now solve for x in each case



So the solutions are 


 {{{x=0}}} or  {{{x=-3}}}



Since the 'x' intercepts of {{{y=5x+x(x-2)}}} are simply the solutions of {{{5x+x(x-2)=0}}}, this means that the x-intercepts are (0,0) and (-3,0)