Question 282448
[y^2 - 7y/y^2 + 8y + 16] + [6y - 20/y^2 + 8y + 16]



[(y^2 - 7y)+(6y-20)]/[y^2 + 8y + 16]



(y^2 - y - 20)/(y^2 + 8y + 16)



((y-5)(y+4))/((y+4)(y+4))



(y-5)/(y+4)



Answer: [y^2 - 7y/y^2 + 8y + 16] + [6y - 20/y^2 + 8y + 16] = (y-5)/(y+4)