Question 282515
First, get it into slope-intercept form:  y = mx + b
where
y = value of y that depends on the value of x
m = slope of the line
b = y-intercept (the point where x=0)
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2y = 6x+4
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Divide both sides of the equation by 2.
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y = 3x + 2
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When x=0
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y = 3*0 + 2 = 2

which defines the point (0,2).
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The x-intercept occurs where y=0.
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0 = 3x + 2
or
3x +2 = 0
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Subtract 2 from both sides.
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3x = -2
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Divide both sides by 3.
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x = -2/3, which defines the point (-2/3,0).
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Given you have two points, you can graph a straight line.
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{{{graph(500,500,-5,5,-5,5,3*x+2)}}}
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That's about all you need to know about this equation.
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y = 3x + 2
The slope = 3, which means it goes up to the right.
The y-intercept = (0,2).
The x-intercept = (-2/3,0).
The graph is shown above.
You could test another value of x to make sure it is on the line, but I leave that to you.
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Done.