Question 282433
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Let *[tex \Large x] represent the 10s digit.  Then *[tex \Large x\ +\ 5] must represent the units digit.


The number is then *[tex \Large 10x\ +\ (x\ +\ 5)\ =\ 11x\ +\ 5], and the sum of the digits is *[tex \Large x\ +\ x\ +\ 5\ =\ 2x\ + \5], and three times the sum of the digits is then *[tex \Large 3(2x\ +\ 5)\ =\ 6x\ +\ 15], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 11x\ +\ 5\ =\ 6x\ +\ 15]


Solve for *[tex \Large x] (which you know has to be 4 or less -- otherwise adding 5 to get the units digit would result in something other than a digit)



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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