Question 282376
what is an equation of the perpendicular bisector of the line between the points, (2,2) and (6,6).
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The slope of the line thru the points is 1 (6-2)/(6-2)
The midpoint is (4,4)
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The slope of the line perpendicular is -1
Use y = mx+b to find the line thru (4,4) and m = -1
4 = -4 + b
b = 8
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--> y = -x + 8
or x + y = 8