<PRE><B>Question 282331</B>
12y^2-5y=2

12y^2-5y-2=0

12y^2-8y+3y-2

4y(3y-2)+1(3y-2)=0

(3y-2)(4y+1)=0

If 3y-2 = 0

3y=2
y=2/3

OR

If 4y+1=0

4y=-1

y=-1/4

</PRE>