Question 282235
1.) logv5 (3x-10)-3logv5 4 = 2 


Using two laws of logs:

log a^b = b*log a  and
log (a- b) = log a - log b

We have from 1.):

logv5 (3x-10) - logv5 4^3 = 2   (note that 4^3 = 64)

logv5 (3x-10)/64 = 2

By definition of a logv5 we have:

(3x-10)/64 = 5^2

3x-10 = 25*64

Solve the above for x.