Question 282233
3x^3+4x^2-32x=0
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separate the common 'x'
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x*(3x^2+4x-32)=0
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factor
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(3x^2+4x-32)=(3x - 8 )(x + 4)
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so...
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x(3x-8)(x+4)=0
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That means there are three roots:
x = 0
x = 8/3
x = -4
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{{{graph(500,500,-10,10,-70,70,3*x^3+4x^2-32*x)}}}