Question 282204
Rearrange the equation into:  y = whatever format
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{{{x^2 + 2y = -2}}}
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subtract x^2 from both sides
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{{{2y = -x^2 -2}}}
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divide both sides by 2
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{{{y = -(-1/2)*x^2 -1}}}
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So you want to know if (2,-3) is on the graph?  Plug the value of 'x' into the equation and see.
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{{{y = -(-1/2)*2^2 -1}}}
{{{y = -(-1/2)*4 -1}}}
{{{y = -2 -1}}}
{{{y = -3}}}

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Yes, the point (2,-3) is on the graph.
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Done