Question 282200
I fixed your question for you I think:

The quadratic formula is 

{{{(-b + sqrt(b^2 - 4ac))/2a}}}

and

{{{(-b - sqrt(b^2 - 4ac))/2a}}}

So you have a = 3, b = 1, c = -5

{{{(-1 + sqrt(61))/6}}}
{{{(-1 - sqrt(61))/6}}}

Two answers, one is plus and minus