Question 282032
First we need to find the sum of these 9 consecutive integers.

If we have some integer X, then (X + 1) will be the next integer, we want 9 integers total so we have:

{{{X + (X + 1) + (X + 2) + (X + 3) + (X + 4) + (X + 5) + (X + 6) + (X + 7) + (X + 8)}}}

Combining like terms we get:

{{{9X}}} plus the sum of (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8). You can either hand calculate this sum or you can use the formula n(n + 1)/2 is the sum of any numbers. So our n in this case is 8 so we have 8 * 9/2 = 36

So we have
{{{9x + 36 = 180}}} 
{{{9x = 144}}}
{{{x = 16}}}

So our 9 terms are:

16, 17, 18, 19, 20, 21, 22, 23, and 24. The mean is the average which is the middle number which is the mean.

So mean = 20 = median, mean - median = median - mean = 0