Question 281950
T(L)=2pi square root(L/32.2) 
The question is to express the length,L as a function of the period T.
---------------------------------
T(L) = 2pi*sqrt(L/32.2)
sqrt(L/32.2) = T(L)/(2pi)
---
Square both sides to get:
L/32.2 = [T(L)/(2pi)]^2
---
L = 32.3[T/2pi]^2
===================
Cheers,
Stan H.