Question 281841
There are indeed numerous ways to do this.


However, an easy way to do this (although not entirely concise!) is to factor 2's.

IE. We know that 2 will factor out as the number is even.

Secondly, we know another 2 will factor out as we will have 16 as the last two digits.

Thirdly, we know yet another 2 will factor out as we will have 58 as the last two digits.

hence, 2^3 is a factor. 2^3=8. hence 8|98765432.

In other words, 8u=98765432 gives u as an integer hence it is exactly divisible.


--- You could solve this using modular arithmetic and a few other ways, but I think this is the most intuitive.