Question 34161
you cannot factorise this quadratic easily, so look to the quadratic formula to help you. By looking at the discriminant, {{{b^2 - 4ac }}}, we see that it is


{{{ (6)^2 - 4(1)(-3) }}}
{{{ 36 + 12 }}}
{{{ 48 }}}


So, the quadratic does have solutions, given by:


{{{ x = (-b +- sqrt(b^2-4ac))/(2a) }}}
{{{ x = (-6 +- sqrt(48))/2 }}}
{{{ x = (-6 +- sqrt(16*3))/2 }}}
{{{ x = (-6 +- sqrt(16)sqrt(3))/2 }}}
{{{ x = (-6 +- 4sqrt(3))/2 }}}
{{{ x = (2(-3 +- 2sqrt(3)))/2 }}}
{{{ x = -3 +- 2sqrt(3) }}}
so {{{ x = -3+2sqrt(3) }}} or {{{ x = -3-2sqrt(3) }}}


jon.