Question 281814


{{{2x-3y=10}}} Start with the given equation.



{{{-3y=10-2x}}} Subtract {{{2x}}} from both sides.



{{{-3y=-2x+10}}} Rearrange the terms.



{{{y=(-2x+10)/(-3)}}} Divide both sides by {{{-3}}} to isolate y.



{{{y=((-2)/(-3))x+(10)/(-3)}}} Break up the fraction.



{{{y=(2/3)x-10/3}}} Reduce.



So the equation {{{y=(2/3)x-10/3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2/3}}} and the y-intercept is {{{b=-10/3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{10}{3}\right)]