Question 281665
If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? 
Use the hang time function V=48T^2
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35 = 48T^2
T^2 = 35/48
T =~ 0.854 hours (weeks? years?) you didn't give the units
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PS   I accept no responsibility for that "function"
I cannot vouch for its validity.