Question 281535
2z^2+3=8z
2z^2-8z+3=0
{{{z = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
z=(8+-sqrt[-8^2-4*2*3])/2*2
z=(8+-sqrt(64-24])/4
z=(8+-sqrt40)/4
z=(8+-6.3246)/4
z=(8+6.3246)/4
z=14.3246/4
z=3.58 ans.
z=(8-6.3246)/4
z=1.6754/4
z=.419 ans.