Question 281617
Here is your question, we need to translate it into equations:

"Find three consecutive odd integers for which three times the smallest is 15 less than the sum of the other two."

let x = smallest odd integer
then x + 2 = next odd integer
then x + 4 = second to next odd integer

{{{ 3x = (x + 2) + (x + 4) - 15}}}

The above equation says 3 times the smallest is equal to the sum of the other two less than 15.

{{{3x  = 2x  - 9 }}} combine like terms
{{{x = -9}}} solving for x

which is true because 3 times -9 is -27 which is 15 less than -12 which is the sum of -7 and -5