Question 34165
Let the number of nickels be x
Let the number of dimes be y
Equation (1):
10y+5x=740
x=148-2y (subsitution)
2(10y)+5(x+20)=1320
20y+5x+100=1320
20y+5(148-2y)+100=1320
20y+740-10y+100=1320
10y=480
y=48
x=148-2(48)
y=52
Hence, there are 48 nickels and 52 dimes.
Paul.