Question 280783
{{{(2*sqrt(7))*(3*sqrt(5))}}}
Since this is all multiplication and since multiplication is Commutative and Associative we can change the order and grouping any way we choose:
{{{(2*3)(sqrt(7)*sqrt(5))}}}
For the square roots we can use the property of radicals, {{{root(a, p) * root(a, q) = root(a, p*q)}}} to multiply them:
{{{6sqrt(35)}}}
The only thing left is to simplify the square root, if possible, by factoring out perfect squares. But 35 has no perfect square factors so it will not simplify.