Question 281408

Lets invest $x at 8% interest then rest of the amount $(5400 - x) will be invested at 10% interest rate.

Now interest earned on 8% rate will be (8/100)*x
and interest earned on 10% rate will be (10/100)*(5400 - x)

But it is given that interest earned are same which means
(8/100)*x = (10/100)*(5400 - x)

solving it

8x = 54000 - 10x
18x = 54000
x = 3000

Therefor amount invested at 8% and 10% are $3000 and $2400 respectively.