Question 281364
The general form of a quadratic equation that has been solved is to have two factors that are multiplied.  In this case, you're told the solutions are x= -3.5 and x=2.2.  So the factored form of the equation would be:
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(x + 3.5)(x - 2.2) = 0
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Using FOIL...
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x^2 -2.2x +3.5x -7.7 = 0
x^2 + 1.3x - 7.7 = 0
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multiply by 10 to get rid of the decimals...
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10x^2 + 13x - 77 = 0
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Checking this equation using the quadratic formula, you can determine if the solutions are x= -3.5 and x= 2.2...
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.*[invoke quadratic "x", 10, 13, -77 ]
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Done