Question 281243
Let width be w and length be l.
{{{l = 2w-1}}}
{{{Area = Length * Width}}}
{{{45 = (2w-1)w}}}
{{{45 = 2w^2 -w}}}
{{{0 = 2w^2 - w - 45}}}
{{{0 = (2w +9)(w - 5)}}}
so either w-5 =0  or 2w+9=o
w = 5 or w = -9/2 
since a distance can't be nagative, width = 5
so length = 2*5-1 = 9

Does 9*5 = 45??