Question 281171
The consecutive odd integers are:
{{{n}}}
{{{n+2}}}
{{{n + 4}}}
given:
{{{4*(n+2 + n + 4) = 10n + 2}}}
{{{4*(2n + 6) = 10n + 2}}}
{{{8n + 24 = 10n + 2}}}
{{{2n = 22}}}
{{{n = 11}}}
{{{n + 2 = 13}}}
{{{n + 4 = 15}}}
The numbers are 11,13, and 15
check:
{{{4*(n+2 + n + 4) = 10n + 2}}}
{{{4*(11+2 + 11 + 4) = 10*11 + 2}}}
{{{4*28 = 110 + 2}}}
{{{112 = 112}}}
OK