Question 281033
(4,3) perpendicular to the line 3x+y=7
when finding the perpendicular line u need to use the opposite reciprical of its slope.
{{{3x+y=7}}} put it in slope intercept form y=mx+b
{{{y=7-3x}}}
{{{y=-3x+7}}}
so {{{-3}}} is the slope of the perpendicular line so the opposite reciprical is {{{1/3}}}
now we have 3 known variables out of 4
{{{y=mx+b}}} use the slope and the point to find the intercept
{{{3=(1/3)4+b}}}
{{{3=(4/3)+b}}}
{{{3-(4/3)=(4/3)-(4/3)+b}}}
{{{(9/3)-(4/3)=b}}}
{{{5/3=b}}}
now re write the slope intercept form with the slope and intercept of the line
{{{y=(1/3)x+(5/3)}}} theres your line