<PRE><B>Question 281002</B>
sketch the triangle and use the law of cosines to find the indicated value.round your answer ro the nearest hundreth. 
22)find the angle opposite the longest side in a triangle with sides of 43 ft ,48ft, and 65ft.
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Since a^2 = b^2 + c^2 -2bc*cos(A)
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cos(A) = (b^2+c^2-a^2)/2bc
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Your Problem:
cos(A) = (43^2+48^2-65^2)/(2*43*48)
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cos(A) = -0.0174
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A = cos^-1(-0.0174) = 91 degrees
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Cheers,
Stan H.</PRE>