Question 280872
Two coins contain only dimes and quarters. The total value of the coins in the first bank is $15. In the second bank, there are 15 more dimes than in the first bank and half as many quaRTERS. The total value of the second bank is $10.25. Find the number of dimes in the first bank.

Let x be the number of dimes in the first bank. Let y be the number of quarters in the first bank.

The number of dimes in the second bank then is x+15. The number for quarters in the second bank is .5*y.

So we have:

First Bank amount:

1.) .10*x + .25y = 15.00

Second Bank amount:

2.) .10*(x+15) + .25*(.5*y) = 10.25

Solve this system of equations for x.