Question 280949
page numbers 1 to 9 = 1 digit per page * 9 pages = 9 digits total.
page numbers 10 to 99 = 2 digits per page * 90 pages = 180 digits total.
page numbers 100 to 999 = 3 digits per page * 900 pages = 2700 digits total.
page numbers 1000 to 9999 = 4 digits per page * 9000 pages = 36000 digits total.


Since the total number of digits is 3001, then:


we ate up 9 digits to get from 1 to 9.
we ate up another 180 digits to get from 10 to 99.
we ate up another 2700 digits to get from 100 to 999.


So far we used a total of 2700 + 180 + 9 = 2889 digits.


Since we need to eventually use a total of 3001 digits, we have 3001 - 2889 = 112 more digits to go, and all of these digits will have 4 digits per page.


If we divide 112 by 4, we get 28 pages to go.


999 + 28 = 1027 pages in the volume.


If I am correct, that would be selection C.


The fact that 112 divided evenly by 4 was a good sign.


I would go with selection C.


A built in assumption is that the page numbers start at 1 and not 0.


this is a fair assumption I believe.