Question 280801
Perimeters are the measure of a shape all the way around the shape.  In the case of a rectangle then, the perimeter is made up of TWO lengths and TWO widths.  If we say "L" is length and "w" is width, then our equation can be:


L + L + w + w = 70.  


According to your information, the Length is 8 meters more than twice the width.  Let's break that down to the following:



The Length:  L
is:  = 
8 meters more than:  8 +
Twice the width:  2w


In other words, the equation is:  L = 8 + 2w.


Now let's write that down according to what we said about the perimeter.  I mean to say that we agreed with the following:


L + L + w + w = 70   Let's plug in what we know for "L"
(8 + 2w) + (8 + 2w) + w + w = 70  See where we plugged in (8 + 2w) for the L variable?  Now let's combine like terms.

16 + 6w = 70  Now let's subtract 16 from both sides to begin to isolate the w.
6w = 70 - 16
6w = 54  Now let's divide both sides by 6 to further isolate the w.
w = 9


AH!  Now we know that the width is 9.


If the Length is 8 meters more than 2 times the width, we can use that equation again.


L = 8 + 2w
L = 8 + 2(9) See where we plugged in 9 for the Width?
L = 8 + 18  (2 times 9 = 18)
L = 26


SO now our width is 9 and our length is 26.   Does this work?  Let's see:


L + L + w + w = 70
26 + 26 + 9 + 9 = 70
70 = 70  YES!  It works.  Yay!


I hope this helps you. :-)