Question 280737
what is {{{3i^11}}}? 
<pre><font size = 4 color = "indigo"><b>
The idea is to get in terms of an even power of i,
then in terms of {{{i^2}}} and then change the {{{i^2}}}
to {{{-1}}}.
{{{3i^11=3i^(10+1)=3i^10*i^1=3i^(2*5)*i=3(i^2)^5*i=3(-1)^5*i=3(-1)*i=-3i}}}
</pre></b></font>Also, what is {{{3i^4*2i^2}}}?
<pre><font size = 4 color = "indigo"><b>
These are already even powers of i. So we write {{{i^4}}} in terms
of {{{i^2}}}, which is {{{-1}}}.  The second factor is already {{{i^2}}}
so we write it {{{-1}}}:
{{{3i^4*2i^2=3i^(2*2)*2(-1)=3(i^2)^2(-2)=3(-1)^2(-2)=3(1)(-2)=-6}}}
Edwin</pre>