Question 280655
First take {{{a= b+2}}} and isolate {{{b-a}}} to get {{{b-a=-2}}}. Now raise both sides to the 4th power to get {{{(b-a)^4=(-2)^4}}}. I'll let you carry out the rest of the computations.


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If we subtract 'x' from both sides on {{{x + 3 > x + 5}}}, we get {{{3>5}}} which is NEVER true for any value of 'x'. So there are NO solutions. This means that the solution set is the empty set. Recall that the empty set is the set with no elements.