Question 280658
First, get it into slope-intercept form:  y = mx+b
m = slope
b = y-intercept
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3y = 12
y = 12/3 = 4
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Now pick two points to define a line:  say x=1 and x= 4
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When x = 1, y = 4
When x = 4, y = 4
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Hmmm....
It appears this is a horizontal line, which means the slope=0.
Observing y = 4 we see that this is the same as y = 0x + 4, which is slope=0.
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{{{graph(500,500,-10,10,-10,10,4)}}}
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Done.