Question 280569
(In the future, please put parentheses aroung multi-term numerators and denominators. Tutors are more likely to respond to a problem that is clearly stated.)
{{{(28x^3-23x^2-47x-18)/(7x+3)}}}
<pre>
       4x^2  -5x    -32/7
      ____________________________
7x+3 /28x^3  -23x^2  -47x  -18
      28x^3  +12x^2
      -------------
             -35x^2  -47x
             -35x^2  -15x
             ------------
                     -32x  -18
                     -32x  -96/7
                     -----------
                           -30/7
</pre>
So {{{(28x^3-23x^2-47x-18)/(7x+3) = 4x^2  -5x    -32/7 + ((-30)/7)/(7x+3)}}}
The remainder fraction will simplify:
{{{(28x^3-23x^2-47x-18)/(7x+3) = 4x^2 -5x -32/7 + (-30)/(7(7x+3)) = 4x^2 -5x -32/7 + (-30)/(49x+21))}}}