Question 280629
The presented problem is in slope-intercept form:  y = mx + b.
m = slope
b = y-intercept.
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y = 8/3x +3
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slope = 8/3
y-intercept = 3
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which defines the point (0,3)
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We know the slope = rise / run = change in y / change in x.
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So for every change of 3 in x, we have a change of 8 in y.
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That allows us to define another point:  (0+3, 8+8) or (3,16)
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You can graph the line using the two points, so pick the x-intercept as another.
The x-intercept is where y=0.
0 = 8/3x +3
-8/3x = 3
-8x = 9
x = -9/8
thus defining the point (-9/8,0)
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{{{graph(500,500,-10,10,-10,10,8/3*x+3)}}}
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