Question 280579
nice expression! what about it?
Do you mean
(28x^3-23x^2-57x-18)/(7x+3)
{{{(28x^3-23x^2-57x-18)/(7x+3)}}}
It reduces to 
{{{ (4x^2-5x-6)(7x-3)/(7x-3)}}}
and then factors to
{{{(x-2)(4x+3)(7x+3)/(7x+3)}}}
Which becomes
{{{(x-2)*(4x+3)}}}