Question 34035
{{{(5/6)}}} = 5t-{{{(4/2)}}}
5t = {{{(5/6)}}}+{{{(4/2)}}}
5t = {{{(5+12)/6}}}
t = {{{(17/30)}}}

i assume the problem must have been 
{{{(5/6)}}} = {{{(5t-4)/2}}}
{{{(5/3)}}} = {{{(5t-4)}}}
5 = 3*(5t-4)
5 = 15t - 12
15t = 17
t = {{{(17/15)}}}