Question 280547
Solve:
{{{25x^2+49 = 0}}}
You're on the right track!
{{{25x^2+49 = 0}}} Subtract 49 from both sides.
{{{25x^2 = -49}}} Take the square root of both sides.
{{{sqrt(25x^2) = sqrt(-49)}}}
{{{5x = 7sqrt(-1)}}} or {{{5x = -7sqrt(-1)}}} Divide both sides by 5.
{{{x = (7/5)sqrt(-1)}}} or {{{x = (-7/5)sqrt(-1)}}} which can also be expressed as:
{{{x = (7/5)i}}} or {{{x = -(7/5)i}}} where: {{{i = sqrt(-1)}}}
There are no real solutions.