Question 280494
y >- 1 puts the answer in quadrants 1 and 2.


2x + y <= 6 needs to be converted to get y on the left side of the equation and the x's on the right sides of the equation.


2x + y <= 6 is the original equation.


subtract 2x from both sides of the equation to get:


y <= -2x + 6


if x is 0, this equation becomes y <= 6
if x is 1, this equation becomes y <= 4
y is defiitely in the first quadrant.
if x is -1, this equation becomes y <= 8
y is definitely in the second quadrant.


Looks like your answer will be first and second quadrant.


A graph of both equations is shown below:


The equations are:


y >= 1
y <= -2x + 6


{{{graph (600,600,-10,10,-10,10,1,-2x+6)}}}


The shaded region is anything on or above the line y = 1, and anything on or below the line y = -2x + 6.


The shaded region is in quadrants 1 and 2.


The shaded region can never be in quadrants 3 and 4 because the value of y has to be greater than 1.