Question 280503
Let the number in the units place be x

then the digit in the tens place will be 6/x


x-(6/x)=1

x^2-6=x

x^2-x-6=0

x^2-3x+2x-6=0
x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x=3 , -2

the other digit =2

So the number is 23