Question 280462
{{{log(2,6) - log(2,3) + 2*log(2,sqrt(8))}}}
The 1st 2 terms are:
{{{log(2,6) - log(2,3) = log(2,6/3)}}}
{{{log(2,6/3) = log(2,2)}}}
{{{log(2,2) = 1}}}
So far I have
{{{1 + 2*log(2,sqrt(8)) = 1 + log(2,(sqrt(8))^2)}}}
{{{1 + log(2,(sqrt(8))^2) = 1 + log(2,8)}}}
{{{1 + log(2,8) = 1 + 3}}}
{{{1 + 3 = 4}}}