Question 280417
{{{A=(1/2)bh}}}
{{{b=sqrt(30)}}}
{{{h=sqrt(6)}}}
{{{A=(1/2)(sqrt(30))(sqrt(6))}}}
{{{A=(sqrt(180))/2}}} find the seperate squares in 180
{{{A=(sqrt(9*4*5))/2}}}the squares {{{3^2}}} and {{{2^2}}} can then be factored
{{{A=(3*2*sqrt(5))/2}}} the 2 canceles
{{{A=3*sqrt(5)}}}