Question 280179
{{{1/(x^2-5x)=(x+7)/(x-1)}}}
{{{x-1=(x+7)(x^2-5x)}}}
{{{x-1=(x^3-5x^2+7x^2-35x)}}}
{{{x-1=x^3+2x^2-35x}}}
{{{x-1-x+1=x^3+2x^2-35x-x+1}}}
{{{0=x^3+2x^2-36x+1}}}
{{{0=x^2(x+2)+(-36x+1)}}}
x+2=0 x=-2
-36x+1=0 x=-1/36