Question 280211
simply replace the x with the value given and solve
h(x)= x^2–4x+5
h(4)= (4^2)–4(4)+5 = 16-16+5 = 5
h(–4)= (-4)^2–4(-4)+5 = 16+16+5 = 37
h(0)= 0^2–4(0)+5 = 5