Question 280177
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There are a couple of ways to look at this.


First is you can consider having multiplied *[tex \Large \frac{5}{7}] by 1 in the form of *[tex \Large \frac{a}{a}], like this:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{5}{7}\right)\left(\frac{a}{a}\right)]


to obtain some number over 98.  That means that *[tex \Large 7a] must equal 98.  And that means you can determine the value of *[tex \Large a] by dividing 98 by 7.  Once you have the value of *[tex \Large a] you can multiply that by 5 to get the numerator you don't know.


The other way is to look a this like a proportion:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{7}\ =\ \frac{x}{98}]


Cross-multiply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 7x\ =\ 5\,\cdot\,98]


and then just solve for *[tex \Large x] which is your missing numerator.




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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