Question 280064
Let the first odd number be given by X. The next consecutive odd is (X+2) and the next after that is (X+4)

You are told the sum of the three numbers is 147
{{{147 = X + (X+2) + (X+4)}}} collect like terms
{{{147 = 3X + 6}}} subtract 6 from each side
{{{141 = 3X}}} divide both sides by 3
{{{47 = X}}}

So one number is 47; then next one is 47+2 = 49. The third odd number is 47+4 = 51

Check your answer. Does 147 = 47+49+51