Question 33976
Let x = the number that can be bought for $20.00 each, then (59-x) = the number that can be bought for $50.00 each. You can write:
$20(x) + $50(59-x) = $2380 Simplify and solve for x.
$20(x) + $2950 - $50x = $2380
-$30(x) + $2950 = $2380 Subtract $2950 from both sides.
-$30(x) = -$570 Divide both sides by -$30.
x = 19
59-x = 40

19 can be bought at $20.00 each
40 can be bought at $50.00 each.